15x^2-6x+50x-20=20x^2+15x

Solution for 15x^2-6x+50x-20=20x^2+15x equation:

15x^2-6x+50x-20=20x^2+15x

We move all terms to the left:

15x^2-6x+50x-20-(20x^2+15x)=0

We add all the numbers together, and all the variables

15x^2+44x-(20x^2+15x)-20=0

We get rid of parentheses

15x^2-20x^2+44x-15x-20=0

We add all the numbers together, and all the variables

-5x^2+29x-20=0

a = -5; b = 29; c = -20;
Δ = b2-4ac
Δ = 292-4·(-5)·(-20)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-21}{2*-5}=\frac{-50}{-10}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+21}{2*-5}=\frac{-8}{-10}
=4/5
$